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Question Number 123294 by roniee last updated on 24/Nov/20
L(y+∫ydt)=L(1−e−t)
Answered by Olaf last updated on 24/Nov/20
L(y+∫ydt)=L(1−e−t)L(p)+L(p)p=1p−1p+1L(p)(p+1p)=1p(p+1)L(p)=1(p+1)2WiththeLaplacetables:y(t)=te−t
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