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Question Number 123410 by bemath last updated on 25/Nov/20
Supposethatfisdifferentiablewithderivativef′(x)=(1+x3)−1/2.Showthatg=f−1satisfiesg″(x)=32g(x)2
Answered by mnjuly1970 last updated on 25/Nov/20
y=f(x)⇒x=f−1(y)(f−1)′(y)=1f′(x)⇒g′(y)=1f′(x)g″(y)y′=−f″(x)(f′)2(x)g″(y)=−f″(x)(f′)3(x)=−−12(3x2)(1+x3)−32(1+x3)−32g″(y)=32x2=32(f−1(y))2g″(y)=32g2(y)✓
Commented by bemath last updated on 25/Nov/20
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