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Question Number 123509 by Jamshidbek2311 last updated on 26/Nov/20
∫π2−π2∣cosx∣=?
Answered by bramlexs22 last updated on 26/Nov/20
=∫π/2−π/2∣cosx∣dx=2∫π/20cosxdx=2(sinx)]0π/2=2
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