a man 6 ft tall walks at a rate of 7 ft/sec away from a lamppost that is 14 ft hight. at what rate is the lenght of his shadow charging when he is 30 ft away from the lamppost


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Question Number 123548 by bramlexs22 last updated on 26/Nov/20

$a m a n 6 f t t a l l w a l k s a t a r a t e$ $o f 7 f t / s e c a w a y f r o m a l a m p p o s t$ $t h a t i s 14 f t h i g h t .$ $a t w h a t r a t e i s t h e l e n g h t o f h i s$ $s h a d o w c h a r g i n g w h e n h e i s 30 f t$ $a w a y f r o m t h e l a m p p o s t$
Commented by bramlexs22 last updated on 26/Nov/20

$a n y o n e h e l p m e$
	Answered by mr W last updated on 26/Nov/20

	Commented by mr W last updated on 26/Nov/20

	$l e n g t h o f s h a d o w = y$ $\frac{x + y}{y} = \frac{14}{6} = \frac{7}{3}$ $y = \frac{3}{4} x$ $\frac{d y}{d t} = \frac{3}{4} \times \frac{d x}{d t} = \frac{3}{4} \times 7 = \frac{21}{4} f t / s$
	Commented by bramlexs22 last updated on 26/Nov/20

	$t h a n k y o u s i r$
	Commented by bramlexs22 last updated on 26/Nov/20
	Why is the 30 ft / sec information not being used sir?
	Commented by mr W last updated on 26/Nov/20

	$t h e r a t e o f c h a n g i n g i s c o n s t a n t,$ $n o m a t t e r w h e r e t h e m a n i s .$
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