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Question Number 123595 by Snail last updated on 26/Nov/20

For real numbers (a/b/c) define s_n =a^n +b^n +c^n   Suppose s_1 =2 s_2 =6 and s_(3 ) =14.Prove that   ∣s_n ^2 −s_(n−1) s_(n+1) ∣=8=holds ∀ n>1

$${For}\:{real}\:{numbers}\:\left({a}/{b}/{c}\right)\:{define}\:{s}_{{n}} ={a}^{{n}} +{b}^{{n}} +{c}^{{n}} \\ $$ $${Suppose}\:{s}_{\mathrm{1}} =\mathrm{2}\:{s}_{\mathrm{2}} =\mathrm{6}\:{and}\:{s}_{\mathrm{3}\:} =\mathrm{14}.{Prove}\:{that}\: \\ $$ $$\mid{s}_{{n}} ^{\mathrm{2}} −{s}_{{n}−\mathrm{1}} {s}_{{n}+\mathrm{1}} \mid=\mathrm{8}={holds}\:\forall\:{n}>\mathrm{1} \\ $$

Commented bySnail last updated on 26/Nov/20

    I had tried using Mathematical  Induction but unabld to solve

$$ \\ $$ $$ \\ $$ $${I}\:{had}\:{tried}\:{using}\:{Mathematical}\:\:{Induction}\:{but}\:{unabld}\:{to}\:{solve} \\ $$ $$ \\ $$

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