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Question Number 123767 by oustmuchiya@gmail.com last updated on 28/Nov/20
Answered by physicstutes last updated on 28/Nov/20
s=2t+3sin2t(i)Initiatpositionoccursatt=0s⇒s0=2(0)+3sin2(0)s0=0m(ii)v=dsdt=2+6cos2ta=dvdt=0−12sin2t⇒v=(2+6cos2t)ms−1anda=(−12sin2t)ms−2(iii)Atrestv=0⇒2+6cos2t=0cos2t=−132t=109.5⇒t=54.75sb.F(x)=250e0.09x,x⩾0dF(x)dx=22.5e0.09xdF(x)dx∣8months=22.5e0.09×8=46.2
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