(√(56+67−6+(6/(99))))


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Question Number 123780 by Ruhiyyeheyret last updated on 28/Nov/20

$\sqrt{56 + 67 - 6 + \frac{6}{99}}$
	Answered by MJS_new last updated on 28/Nov/20
	$1. reduce the fraction ((a×c)/(b×c))=(a/b) 2. add/substract the integers 3. add the integer and the fraction a+(b/c)=((ac+b)/c) 4. if possible, reduce the fraction again 5. check both the numerator and the denominator for square factors 6. (√((a×b^2 )/(c×d^2 )))=(b/d)×(√(a/c)) (7. if desired (b/d)×(√(a/c))=((b(√(a×c)))/(c×d)))$
	$1 . reduce the fraction \frac{a \times c}{b \times c} = \frac{a}{b}$ $2 . add / substract the integers$ $3 . add the integer and the fraction a + \frac{b}{c} = \frac{a c + b}{c}$ $4 . if possible, reduce the fraction again$ $5 . check both the numerator and the denominator for square factors$ $6 . \sqrt{\frac{a \times b^{2}}{c \times d^{2}}} = \frac{b}{d} \times \sqrt{\frac{a}{c}}$ $(7 . if desired \frac{b}{d} \times \sqrt{\frac{a}{c}} = \frac{b \sqrt{a \times c}}{c \times d})$
	Commented by Ar Brandon last updated on 28/Nov/20
	�� Nice one, Sir
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