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Question Number 123829 by Algoritm last updated on 28/Nov/20

Commented by Algoritm last updated on 28/Nov/20

$$\mathrm{prove}\mathrm{that}$$

Commented by mr W last updated on 28/Nov/20

$$x=\frac{100k}{99}withk\in [0,98]$$

Answered by Snail last updated on 28/Nov/20

$$\frac{x}{100}=x-\lfloor x\rfloor$$$$\lfloor x\rfloor =\frac{99x}{100}$$$$nowlet\lfloor x\rfloor =m$$$$x=\frac{100m}{99}$$$$wherem\in [0,98]becauseof0⩽\left\{x\right\}<1$$

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