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Question Number 123922 by help last updated on 29/Nov/20

	Answered by liberty last updated on 29/Nov/20
	$y=p(x−3)^2 +1 = px^2 −6px+9p+1 { ((p=−a)),((b=−6p )),((c=9p+1)) :}$
	$y = p {(x - 3)}^{2} + 1 = {p x}^{2} - 6 p x + 9 p + 1$ ${\begin{cases} p = - a \\ b = - 6 p \\ c = 9 p + 1 \end{cases}$
	Commented by help last updated on 29/Nov/20

	$v a l u e o f p ?$
	Commented by help last updated on 29/Nov/20

	$f r o m h e r e w e c a n s a y o p t i o n A$ $i s v a l i d . . . i s o l v e w i t h g r a p h t h o$ $t h a n k s$
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