find ∫∫_D ((arctan((√(x^2 +y^2 ))))/(x+y))dxdy D={(x,y) / 0≤x≤1 and 1≤y≤2}


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Question Number 124063 by Bird last updated on 30/Nov/20
$find ∫∫_D ((arctan((√(x^2 +y^2 ))))/(x+y))dxdy D={(x,y) / 0≤x≤1 and 1≤y≤2}$
$f i n d \int \int_{D} \frac{a r c t a n (\sqrt{x^{2} + y^{2}})}{x + y} d x d y$ $D = {(x, y) / 0 ⩽ x ⩽ 1 a n d 1 ⩽ y ⩽ 2}$
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