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Question Number 124101 by Ar Brandon last updated on 30/Nov/20
∫(x−6−644+2x−1+x−2⋅x24−4x−1+x−2−4x2(2x+1)1−2x)dx
Answered by MJS_new last updated on 30/Nov/20
=∫2x+1dx=x2+x+C
Commented by Ar Brandon last updated on 30/Nov/20
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