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Question Number 124135 by bramlexs22 last updated on 01/Dec/20

B = ∫_0 ^2 [(√((4−x)/x)) − (√(x/(4−x))) ] dx

B=∫20[4−xx−x4−x]dx

Answered by nico last updated on 01/Dec/20

=∫_0 ^2 ((4−x−x)/(√(4x−x^2 )))dx=∫_0 ^2 ((d(4x−x^2 ))/(√(4x−x^2 ))) =2(√(4x−x^2 ))∣_0 ^2 =4

=∫024−x−x4x−x2dx=∫02d(4x−x2)4x−x2=24x−x2∣02=4

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