How many 6 digit odd numbers have different digits?


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Question Number 124237 by mr W last updated on 01/Dec/20

$H o w m a n y 6 d i g i t o d d n u m b e r s h a v e$ $d i f f e r e n t d i g i t s ?$
Commented by mr W last updated on 02/Dec/20

$5 \times (P_{5}^{9} - P_{4}^{8}) = 67200$
	Answered by liberty last updated on 01/Dec/20

	$c a s e (1) A ◻ ◻ ◻ ◻ B w h e r e A a n d B o d d n u m b e r$ $= 5 \times P_{4}^{8} \times 4$ $c a s e (2) A ◻ ◻ ◻ ◻ B w h e r e A e v e n a n d B o d d n u m b e r$ $= 4 \times P_{4}^{8} \times 5$ $t o t a l l y = P_{4}^{8} \times 40 = \frac{8 \times 7 \times 6 \times 5 \times 4!}{4!} \times 40$ $= 56 \times 30 \times 40 = 67200$ $56 \times 30 \times 40$ $67200.0$
	Commented by mr W last updated on 02/Dec/20

	$c o r r e c t s i r, t h a n k s!$
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