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Question Number 124352 by Mammadli last updated on 02/Dec/20

$$\underset{0}{\stackrel{4\pi }{\int }}\parallel cosx\parallel =?$$

Commented by mr W last updated on 02/Dec/20

$$doyoumean\underset{0}{\stackrel{4\pi }{\int }}\mid cosx\mid dx?$$

Commented by Mammadli last updated on 02/Dec/20

Dear Ser, as I mentioned, it was given..

Commented by mr W last updated on 02/Dec/20

$$\underset{0}{\stackrel{4\pi }{\int }}\mid cosx\mid dx$$$$=8\underset{0}{\stackrel{\frac{\pi }{2}}{\int }}cosxdx$$$$=8{\left[\sin x\right]}_0^{\frac{\pi }{2}}$$$$=8(1-0)$$$$=8$$

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