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Question Number 124393 by n0y0n last updated on 03/Dec/20

Answered by Kunal12588 last updated on 03/Dec/20

1. l_1 :−i+3j+2k+ν(−3i−j−4k) (5,λ,μ) lies on l_1 ⇒ν=((5+1)/(−3))=−2 λ=3−ν=5 μ=2−4ν=10

1.l1:−i+3j+2k+ν(−3i−j−4k)(5,λ,μ)liesonl1⇒ν=5+1−3=−2λ=3−ν=5μ=2−4ν=10

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