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Question Number 124423 by ZiYangLee last updated on 03/Dec/20

If (√(213−4x^2 ))−2(√(12−x^2 ))=11, find the value of (√(213−4x^2 ))+2(√(12−x^2 )).

If213−4x2−212−x2=11,findthevalueof213−4x2+212−x2.

Commented by ZiYangLee last updated on 03/Dec/20

Answer: 15

Answer:15

Answered by Olaf last updated on 03/Dec/20

(√(213−4x^2 ))−2(√(12−x^2 )) = (((213−4x^2 )−4(12−x^2 ))/( (√(213−4x^2 ))+2(√(12−x^2 )))) = ((213−4×12)/( (√(213−4x^2 ))+2(√(12−x^2 )))) = ((165)/( (√(213−4x^2 ))+2(√(12−x^2 )))) = ((15×11)/( (√(213−4x^2 ))+2(√(12−x^2 )))) = 11 ⇒ (√(213−4x^2 ))+2(√(12−x^2 )) = 15

213−4x2−212−x2=(213−4x2)−4(12−x2)213−4x2+212−x2=213−4×12213−4x2+212−x2=165213−4x2+212−x2=15×11213−4x2+212−x2=11⇒213−4x2+212−x2=15

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