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Question Number 124707 by Mammadli last updated on 05/Dec/20

1. A=(3152) ,  A^(−1) =?  2. Solve the equation:  ∣2x611∣=0  3. Calculate the determinant:  ∣132 21 13 42∣

$$\mathrm{1}.\:\boldsymbol{{A}}=\left(\mathrm{3152}\right)\:,\:\:\boldsymbol{{A}}^{−\mathrm{1}} =? \\ $$$$\mathrm{2}.\:\boldsymbol{{Solve}}\:\boldsymbol{{the}}\:\boldsymbol{{equation}}: \\ $$$$\mid\mathrm{2}\boldsymbol{{x}}\mathrm{611}\mid=\mathrm{0} \\ $$$$\mathrm{3}.\:\boldsymbol{{Calculate}}\:\boldsymbol{{the}}\:\boldsymbol{{determinant}}: \\ $$$$\mid\mathrm{132}\:\mathrm{21}\:\mathrm{13}\:\mathrm{42}\mid \\ $$

Commented by MJS_new last updated on 05/Dec/20

once you open a new question there′s a menue  on top:  help ∣_(Color) ^(Font&) ∣_(Drawing) ^(Insert) ∣_(&Tables) ^(Matrix) ∣...  use this so we are able to understand what  you mean

$$\mathrm{once}\:\mathrm{you}\:\mathrm{open}\:\mathrm{a}\:\mathrm{new}\:\mathrm{question}\:\mathrm{there}'\mathrm{s}\:\mathrm{a}\:\mathrm{menue} \\ $$$$\mathrm{on}\:\mathrm{top}: \\ $$$$\mathrm{help}\:\mid_{\mathrm{Color}} ^{\mathrm{Font\&}} \mid_{\mathrm{Drawing}} ^{\mathrm{Insert}} \mid_{\&\mathrm{Tables}} ^{\mathrm{Matrix}} \mid... \\ $$$$\mathrm{use}\:\mathrm{this}\:\mathrm{so}\:\mathrm{we}\:\mathrm{are}\:\mathrm{able}\:\mathrm{to}\:\mathrm{understand}\:\mathrm{what} \\ $$$$\mathrm{you}\:\mathrm{mean} \\ $$

Commented by Mammadli last updated on 05/Dec/20

Dear ser, was written as I wrote

Answered by liberty last updated on 05/Dec/20

do you meant A= (((3     1)),((5     2)) ) ?    A^(−1)  = (1/(6−5))  (((   2     −1)),((−5       3)) ) =  (((   2      −1)),((−5         3)) )

$${do}\:{you}\:{meant}\:{A}=\begin{pmatrix}{\mathrm{3}\:\:\:\:\:\mathrm{1}}\\{\mathrm{5}\:\:\:\:\:\mathrm{2}}\end{pmatrix}\:?\: \\ $$$$\:{A}^{−\mathrm{1}} \:=\:\frac{\mathrm{1}}{\mathrm{6}−\mathrm{5}}\:\begin{pmatrix}{\:\:\:\mathrm{2}\:\:\:\:\:−\mathrm{1}}\\{−\mathrm{5}\:\:\:\:\:\:\:\mathrm{3}}\end{pmatrix}\:=\:\begin{pmatrix}{\:\:\:\mathrm{2}\:\:\:\:\:\:−\mathrm{1}}\\{−\mathrm{5}\:\:\:\:\:\:\:\:\:\mathrm{3}}\end{pmatrix} \\ $$

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