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Question Number 124722 by I want to learn more last updated on 05/Dec/20

Answered by mr W last updated on 05/Dec/20

Commented by mr W last updated on 05/Dec/20

tan θ=((13550)/r)  (2π−2θ)r=13550  2(π−θ)r=r tan θ  2(π−θ)=tan θ  ⇒θ=1.305  ⇒r=((13550)/(tan θ))≈3689

tanθ=13550r(2π2θ)r=135502(πθ)r=rtanθ2(πθ)=tanθθ=1.305r=13550tanθ3689

Commented by I want to learn more last updated on 12/Dec/20

I appreciate sir

Iappreciatesir

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