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Question Number 124797 by oustmuchiya@gmail.com last updated on 06/Dec/20

Answered by benjo_mathlover last updated on 06/Dec/20

Q2) 2p^2 +p−10=0 (2p+5)(p−2)=0 p=2 ⇒3^x = 2 = 3^(log _3 (2)) x = log _3 (2) p = −(5/2) (rejected) since 3^x > 0 , ∀x ∈ R

Q2)2p2+p−10=0(2p+5)(p−2)=0p=2⇒3x=2=3log3(2)x=log3(2)p=−52(rejected)since3x>0,∀x∈R

Answered by benjo_mathlover last updated on 06/Dec/20

Q1) { ((4A−7B = 30)),((−A+B = −6)) :} ⇒ B = A−6 ⇒ 4A−7A+42 = 30 ⇒−3A = −12 ; A = 4 ∧ B = −2

Q1){4A−7B=30−A+B=−6⇒B=A−6⇒4A−7A+42=30⇒−3A=−12;A=4∧B=−2

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