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Question Number 124824 by ZiYangLee last updated on 06/Dec/20

How many positive four-digits integers  abcd satisfy the following conditions:  (i) abcd is divisible hy 7;  (ii) When the first and the last digits     are interchanged, the resulting number     dbca is still a positive four-digits number     that is divisible by 7.

$$\mathrm{How}\:\mathrm{many}\:\mathrm{positive}\:\mathrm{four}-\mathrm{digits}\:\mathrm{integers} \\ $$$${abcd}\:\mathrm{satisfy}\:\mathrm{the}\:\mathrm{following}\:\mathrm{conditions}: \\ $$$$\left(\mathrm{i}\right)\:{abcd}\:\mathrm{is}\:\mathrm{divisible}\:\mathrm{hy}\:\mathrm{7}; \\ $$$$\left(\mathrm{ii}\right)\:\mathrm{When}\:\mathrm{the}\:\mathrm{first}\:\mathrm{and}\:\mathrm{the}\:\mathrm{last}\:\mathrm{digits} \\ $$$$\:\:\:\mathrm{are}\:\mathrm{interchanged},\:\mathrm{the}\:\mathrm{resulting}\:\mathrm{number} \\ $$$$\:\:\:{dbca}\:\mathrm{is}\:\mathrm{still}\:\mathrm{a}\:\mathrm{positive}\:\mathrm{four}-\mathrm{digits}\:\mathrm{number} \\ $$$$\:\:\:\mathrm{that}\:\mathrm{is}\:\mathrm{divisible}\:\mathrm{by}\:\mathrm{7}. \\ $$

Commented by mr W last updated on 06/Dec/20

abcd must be different digits?

$${abcd}\:{must}\:{be}\:{different}\:{digits}? \\ $$

Commented by ZiYangLee last updated on 06/Dec/20

well as the original question does not  mention it, i think abcd can be same  digits also (?

$${well}\:{as}\:{the}\:{original}\:{question}\:{does}\:{not} \\ $$$${mention}\:{it},\:{i}\:{think}\:{abcd}\:{can}\:{be}\:{same} \\ $$$${digits}\:{also}\:\left(?\right. \\ $$

Commented by mr W last updated on 06/Dec/20

then  (i)  1001,1008,1015,...,9996  ⇒1+((9996−1001)/7)=1286 numbers

$${then} \\ $$$$\left({i}\right) \\ $$$$\mathrm{1001},\mathrm{1008},\mathrm{1015},...,\mathrm{9996} \\ $$$$\Rightarrow\mathrm{1}+\frac{\mathrm{9996}−\mathrm{1001}}{\mathrm{7}}=\mathrm{1286}\:{numbers} \\ $$

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