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Question Number 124906 by Mammadli last updated on 06/Dec/20
∫sinx3dx=?
Commented by Dwaipayan Shikari last updated on 06/Dec/20
∫sinx3dx=12i∫eix3−e−ix3dx=ixix36x2Γ(13,ix3)+ix−ix36x2Γ(13,−ix3)(Incompletegamma)
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