find the real values of x for which the function f(x)=(x^2 /(x^2 +3x+2))


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Question Number 12495 by shardon last updated on 23/Apr/17

$f i n d t h e r e a l v a l u e s o f x f o r w h i c h$ $t h e f u n c t i o n f (x) = \frac{x^{2}}{x^{2} + 3 x + 2}$
Commented by mrW1 last updated on 23/Apr/17

$t h e q u e s t i o n i s n o t c o m p l e t e!$
Commented by shardon last updated on 23/Apr/17

$y e s i t d o e s$
Commented by mrW1 last updated on 23/Apr/17

$w h a t i s y o u r q u e s t i o n t h e n ?$
	Answered by FilupS last updated on 24/Apr/17
	$f(x)=(x^2 /(x^2 +3x+2)) x∈R x^2 +3x+2≠0 ⇒ x≠−2, −1 ∀x∈R\{−2, −1}⇒f∈R$
	$f (x) = \frac{x^{2}}{x^{2} + 3 x + 2}$ $x \in R$ $x^{2} + 3 x + 2 \neq 0 \Rightarrow x \neq - 2, - 1$ $\forall x \in R ∖ {- 2, - 1} \Rightarrow f \in R$
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