Question Number 125006 by Mammadli last updated on 07/Dec/20
$$\boldsymbol{{prove}}\:\boldsymbol{{that}}: \\ $$ $$\frac{\mathrm{1}}{\mathrm{3}}+\frac{\mathrm{1}}{\mathrm{4}}+...+\frac{\mathrm{1}}{\mathrm{127}}+\frac{\mathrm{1}}{\mathrm{128}}>\mathrm{1} \\ $$
Commented bymr W last updated on 07/Dec/20
$${that}'{s}\:{too}\:{easy}. \\ $$ $${try}\:{to}\:{prove} \\ $$ $$\frac{\mathrm{1}}{\mathrm{3}}+\frac{\mathrm{1}}{\mathrm{4}}+...+\frac{\mathrm{1}}{\mathrm{127}}+\frac{\mathrm{1}}{\mathrm{128}}>\mathrm{3} \\ $$
Commented byMammadli last updated on 07/Dec/20
Sorry dear, >3