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Question Number 125050 by bramlexs22 last updated on 08/Dec/20
∫π0ecosxecosx+e−cosxdx=?
Answered by liberty last updated on 08/Dec/20
replacexbyπ−xI=∫π0ecosxecosx+e−cosxdxI=∫0πe−cosxe−cosx+ecosx(−dx)I=∫π0e−cosxe−cosx+ecosxdxweget2I=∫π0ecosx+e−cosxecosx+e−cosxdx2I=∫π0dx;I=π2
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