Find the number of real roots of ax^7 −4x^4 +x^2 +1=0 where a>2


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Question Number 125132 by Snail last updated on 09/Dec/20

$F i n d t h e n u m b e r o f r e a l r o o t s o f {a x}^{7} - 4 x^{4} + x^{2} + 1 = 0$ $w h e r e a > 2$
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