Question and Answers Forum

All Questions      Topic List

None Questions

Previous in All Question      Next in All Question      

Previous in None      Next in None      

Question Number 125424 by joki last updated on 11/Dec/20

Answered by bramlexs22 last updated on 11/Dec/20

∫ ((d(x^2 +1))/(2(x^2 +1)^2 )) = (1/2)∫ (x^2 +1)^(−2) d(x^2 +1)  = −(1/(2(x+1))) + c

$$\int\:\frac{{d}\left({x}^{\mathrm{2}} +\mathrm{1}\right)}{\mathrm{2}\left({x}^{\mathrm{2}} +\mathrm{1}\right)^{\mathrm{2}} }\:=\:\frac{\mathrm{1}}{\mathrm{2}}\int\:\left({x}^{\mathrm{2}} +\mathrm{1}\right)^{−\mathrm{2}} {d}\left({x}^{\mathrm{2}} +\mathrm{1}\right) \\ $$$$=\:−\frac{\mathrm{1}}{\mathrm{2}\left(\boldsymbol{{x}}+\mathrm{1}\right)}\:+\:\boldsymbol{{c}}\: \\ $$

Answered by Ñï= last updated on 11/Dec/20

Terms of Service

Privacy Policy

Contact: info@tinkutara.com