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Question Number 12552 by @ANTARES_VY last updated on 25/Apr/17

Find  the  expression.  ((x^2 +2x+8)/(x^2 +2x+3.))

Findtheexpression.x2+2x+8x2+2x+3.

Answered by ajfour last updated on 25/Apr/17

if you mean the range then  y=((x^2 +2x+8)/(x^2 +2x+3)) = 1+(5/((x+1)^2 +2))  y_(max) =1+(5/2)=(7/2)  when (x+1)=0  y_(min) → 1 when x→∞  so the range of the expression is  y∈(1,(7/2)] .

ifyoumeantherangetheny=x2+2x+8x2+2x+3=1+5(x+1)2+2ymax=1+52=72when(x+1)=0ymin1whenxsotherangeoftheexpressionisy(1,72].

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