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Question Number 125523 by Algoritm last updated on 11/Dec/20

Answered by Dwaipayan Shikari last updated on 11/Dec/20

$$\underset{x\to \mathrm{\infty }}{\lim }(2x+3)log\left(\frac{x+2}{x}\right)$$$$=(2x+3)\left(\frac{2}{x}\right)=4+\frac{6}{x}=4\underset{z\to 0}{\lim }log(1+z)=z$$

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