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Question Number 125538 by Mammadli last updated on 11/Dec/20

$$\sqrt{-\mathit{z}}=\mathit{z}+6;(\mathit{z}=?)$$

Answered by mr W last updated on 12/Dec/20

$$letx=\sqrt{-z}>0$$$$\Rightarrow z=-x^2$$$$\Rightarrow x=-x^2+6$$$$\Rightarrow x^2+x-6=0$$$$\Rightarrow (x+3)(x-2)=0$$$$\Rightarrow x=2,-3<0\left(rejected\right)$$$$\Rightarrow z=-2^2=-4$$

Commented by Mammadli last updated on 12/Dec/20

Dear sir, how to answer only -4 or not...

Commented by mr W last updated on 12/Dec/20

$$youareright.x⩾0!$$

Commented by Mammadli last updated on 12/Dec/20

$$\mathit{d}\mathit{e}\mathit{a}\mathit{r}\mathit{s}\mathit{i}\mathit{r},\mathit{x}⩾-6\mathit{m}\mathit{u}\mathit{s}\mathit{t}\mathit{p}\mathit{a}\mathit{y}\mathit{t}\mathit{h}\mathit{e}\mathit{c}\mathit{o}\mathit{n}\mathit{d}\mathit{i}\mathit{t}\mathit{i}\mathit{o}\mathit{n}..$$

Commented by Mammadli last updated on 12/Dec/20

$$\mathit{t}\mathit{h}\mathit{k}\mathit{s}\mathit{d}\mathit{e}\mathit{a}\mathit{r}\mathit{s}\mathit{i}\mathit{r}$$

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