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Question Number 125575 by ZiYangLee last updated on 12/Dec/20

If lim_(x→a) ((x^2 −bx+4b)/(x−a))=−6, find a and b.

Iflimx→ax2−bx+4bx−a=−6,findaandb.

Answered by ajfour last updated on 12/Dec/20

a^2 −ab+4b=0 2a−b=−6 ⇒ a^2 +(2a+6)(4−a)=0 ⇒ a^2 −2a−24=0 ⇒ (a−1)^2 =25 ⇒ a=1±5 (a,b)≡(6, 18), (−4, −2)

a2−ab+4b=02a−b=−6⇒a2+(2a+6)(4−a)=0⇒a2−2a−24=0⇒(a−1)2=25⇒a=1±5(a,b)≡(6,18),(−4,−2)

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