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Question Number 12558 by @ANTARES_VY last updated on 25/Apr/17

$$\mathbf{This}$$$$\mathbf{y}=-{\mathbf{x}}^2+6\mathbf{x}-12\mathbf{find}\mathbf{the}\mathbf{values}$$$$\mathbf{of}\mathbf{the}\mathbf{function}\mathbf{area}.$$

Answered by ajfour last updated on 25/Apr/17

$$y=-12-[{(x-3)}^2-9]$$$$=-3-{(x-3)}^2$$$$rangeoffunctionis$$$$y\in (-\mathrm{\infty },-3).$$

Commented by mrW1 last updated on 25/Apr/17

$$y\in (-\mathrm{\infty },-3]$$$$$$

Commented by ajfour last updated on 25/Apr/17

$$yesofcourse.$$

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