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Question Number 12562 by @ANTARES_VY last updated on 25/Apr/17

$$\mathbf{y}=-\frac{{\mathbf{x}}^3}{3}+2{\mathbf{x}}^2-3\mathbf{x}$$$$\mathbf{maximum}-\mathbf{minimum}=?$$

Commented by sandy_suhendra last updated on 25/Apr/17

$$\mathrm{do}\mathrm{you}\mathrm{mean}{}^{″}\max {\mathrm{stationary}}^{″}\mathrm{and}{}^{″}\min {\mathrm{stationary}}^{″}?$$

Answered by mrW1 last updated on 25/Apr/17

$$y=-\frac{x}{3}(x^2-6x+9)=-\frac{x}{3}{(x-3)}^2$$$$y_{min}\to -\mathrm{\infty }withx\to +\mathrm{\infty }$$$$y_{max}\to +\mathrm{\infty }withx\to -\mathrm{\infty }$$$$$$$$\mathbf{maximum}-\mathbf{minimum}\to \mathrm{\infty }$$

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