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Question Number 125666 by fajri last updated on 12/Dec/20

solution :    x′ =  (((−2        1)),((1        −2)) )x +  (((2e^(−m) )),((3m)) )

$${solution}\:: \\ $$$$ \\ $$$${x}'\:=\:\begin{pmatrix}{−\mathrm{2}\:\:\:\:\:\:\:\:\mathrm{1}}\\{\mathrm{1}\:\:\:\:\:\:\:\:−\mathrm{2}}\end{pmatrix}{x}\:+\:\begin{pmatrix}{\mathrm{2}{e}^{−{m}} }\\{\mathrm{3}{m}}\end{pmatrix} \\ $$

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