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Question Number 125670 by mathocean1 last updated on 12/Dec/20
N<10200,Nhasfivedigits. N≡22[23]andN≡5[17]. DeterminatetheintegerN.
Answered by floor(10²Eta[1]) last updated on 12/Dec/20
10000⩽N<10200 N≡22(mod23)⇒N=23a+22,a∈Z N≡5(mod17)⇒23a+22≡6a+5≡5(mod17) ⇒6a≡0(mod17)⇒a≡0(mod17) ⇒a=17b∴N=391b+22,b∈Z 10000⩽391b+22<10200 9978⩽391b<10178 26⩽b⩽26⇒b=26 ⇒N=391.26+22 N=10188
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