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Question Number 125670 by mathocean1 last updated on 12/Dec/20

N<10200 , N has five digits.  N≡22[23] and N≡5[17].  Determinate the integer N.

N<10200,Nhasfivedigits. N22[23]andN5[17]. DeterminatetheintegerN.

Answered by floor(10²Eta[1]) last updated on 12/Dec/20

10000≤N<10200  N≡22(mod23)⇒N=23a+22, a∈Z  N≡5(mod17)⇒23a+22≡6a+5≡5(mod17)  ⇒6a≡0(mod17)⇒a≡0(mod17)  ⇒a=17b∴N=391b+22, b∈Z  10000≤391b+22<10200  9978≤391b<10178  26≤b≤26⇒b=26  ⇒N=391.26+22  N=10188

10000N<10200 N22(mod23)N=23a+22,aZ N5(mod17)23a+226a+55(mod17) 6a0(mod17)a0(mod17) a=17bN=391b+22,bZ 10000391b+22<10200 9978391b<10178 26b26b=26 N=391.26+22 N=10188

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