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Question Number 125858 by bramlexs22 last updated on 14/Dec/20

Commented by mr W last updated on 14/Dec/20

13×26×2×62.4×1=42 182 ft−lb

13×26×2×62.4×1=42182ftlb

Commented by bramlexs22 last updated on 14/Dec/20

sir how with integral method?

sirhowwithintegralmethod?

Commented by mr W last updated on 14/Dec/20

dW=ρAhdh  W=ρA∫_0 ^H hdh=((ρAH^2 )/2)=ρV(H/2)  =62.4×13×26×2×(2/2)=42 182 ft−lb

dW=ρAhdhW=ρA0Hhdh=ρAH22=ρVH2=62.4×13×26×2×22=42182ftlb

Commented by bramlexs22 last updated on 14/Dec/20

thank you sir

thankyousir

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