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Question Number 12596 by @ANTARES_VY last updated on 26/Apr/17

y=−x^2 +bx+c x=−1 point function accepts a maximum value equal to 5. Find y(1).

y=−x2+bx+cx=−1pointfunctionacceptsamaximumvalueequalto5.Findy(1).

Answered by ajfour last updated on 26/Apr/17

y=c−[(x−(b/2))^2 −(b^2 /4)] has maximum at x=(b/2) so (b/2)=−1 ⇒ b=−2 the maximum value being c+(b^2 /4) =5 ⇒ c=5−(b^2 /4)= 5−(4/4)=4 y= −x^2 −2x+4 =5−(x+1)^2 y(1)=−1+b+c = −1−2+4=1 .

y=c−[(x−b2)2−b24]hasmaximumatx=b2sob2=−1⇒b=−2themaximumvaluebeingc+b24=5⇒c=5−b24=5−44=4y=−x2−2x+4=5−(x+1)2y(1)=−1+b+c=−1−2+4=1.

Commented by @ANTARES_VY last updated on 26/Apr/17

error answer

erroranswer

Commented by ajfour last updated on 26/Apr/17

now ?

now?

Commented by @ANTARES_VY last updated on 26/Apr/17

The answer should be 1.

Theanswershouldbe1.

Commented by @ANTARES_VY last updated on 26/Apr/17

A series please

Aseriesplease

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