Question and Answers Forum

All Questions      Topic List

Arithmetic Questions

Previous in All Question      Next in All Question      

Previous in Arithmetic      Next in Arithmetic      

Question Number 125977 by liberty last updated on 16/Dec/20

 Suppose you put $3000 in a savings account  with a 5% annual interesrate , compounded  continously . How long would it take for  your money tl double ?

$$\:{Suppose}\:{you}\:{put}\:\$\mathrm{3000}\:{in}\:{a}\:{savings}\:{account} \\ $$$${with}\:{a}\:\mathrm{5\%}\:{annual}\:{interesrate}\:,\:{compounded} \\ $$$${continously}\:.\:{How}\:{long}\:{would}\:{it}\:{take}\:{for} \\ $$$${your}\:{money}\:{tl}\:{double}\:?\: \\ $$

Answered by bramlexs22 last updated on 16/Dec/20

P_n  = P_o e^(rt)   ⇔ 6000=3000.e^(t/(20))   ⇔2 = e^(t/(20))  ; (t/(20)) = ln (2)  ⇔t = 20 ln (2); t ≈ 13.86 years  20×ln 2  13.862944

$${P}_{{n}} \:=\:{P}_{{o}} {e}^{{rt}} \\ $$$$\Leftrightarrow\:\mathrm{6000}=\mathrm{3000}.{e}^{\frac{{t}}{\mathrm{20}}} \\ $$$$\Leftrightarrow\mathrm{2}\:=\:{e}^{\frac{{t}}{\mathrm{20}}} \:;\:\frac{{t}}{\mathrm{20}}\:=\:\mathrm{ln}\:\left(\mathrm{2}\right) \\ $$$$\Leftrightarrow{t}\:=\:\mathrm{20}\:\mathrm{ln}\:\left(\mathrm{2}\right);\:{t}\:\approx\:\mathrm{13}.\mathrm{86}\:{years} \\ $$$$\mathrm{20}×\mathrm{ln}\:\mathrm{2} \\ $$$$\mathrm{13}.\mathrm{862944} \\ $$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com