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Question Number 126010 by bramlexs22 last updated on 16/Dec/20

Answered by liberty last updated on 16/Dec/20

$$TheareaofatringleisA=\frac{1}{2}\left(8\right)\left(6\right)\sin \theta$$$$A=24\sin \theta$$$$\frac{dA}{dt}=\left(24\cos \theta \right)\frac{d\theta }{dt};where\frac{d\theta }{dt}=0.12rad/sec$$$$\iff \frac{dA}{dt}=24\times 0.12\times \cos \frac{\pi }{6}=2.49m^2/sec$$$$$$

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