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Question Number 126070 by benjo_mathlover last updated on 17/Dec/20

Commented by liberty last updated on 17/Dec/20

h(x)=∫_1 ^( x) f(t) dt ⇔ h′(x)= f(x)  h′(4)=f(4)= 2

$${h}\left({x}\right)=\int_{\mathrm{1}} ^{\:{x}} {f}\left({t}\right)\:{dt}\:\Leftrightarrow\:{h}'\left({x}\right)=\:{f}\left({x}\right) \\ $$$${h}'\left(\mathrm{4}\right)={f}\left(\mathrm{4}\right)=\:\mathrm{2} \\ $$$$ \\ $$

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