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Question Number 126082 by amns last updated on 17/Dec/20

$$\mathbf{There}\mathbf{is}\mathbf{only}\mathbf{a}\mathbf{three}-\mathbf{digit}\mathbf{number}\mathbf{which}\mathbf{is}\mathbf{a}\mathbf{square}$$$$\mathbf{and}\mathbf{also}\mathbf{a}\mathbf{cube}.\mathbf{Now}\mathbf{can}\mathbf{you}\mathbf{tell}\mathbf{me}\mathbf{what}\mathbf{is}\mathbf{the}\mathbf{number}?$$$$$$$$$$$$$$$$\left[Helpme\right]$$

Commented by mr W last updated on 17/Dec/20

$$729={27}^2=9^3$$

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