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Question Number 12610 by tawa last updated on 26/Apr/17

$$\mathrm{A}\mathrm{steam}\mathrm{engine}\mathrm{of}\mathrm{efficiency}50\mathrm{\%}\mathrm{burns}\mathrm{a}1\mathrm{g}\mathrm{of}\mathrm{coal}\mathrm{to}\mathrm{produce}10000\mathrm{J}$$$$\mathrm{of}\mathrm{energy}.\mathrm{if}\mathrm{it}\mathrm{burns}20\mathrm{g}\mathrm{per}\sec ,\mathrm{calculate}\mathrm{the}\mathrm{output}\mathrm{power}.$$

Answered by mrW1 last updated on 27/Apr/17

$$P=0.5\times 20\times 10000=100000Watt=100kW$$

Commented by tawa last updated on 27/Apr/17

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}.$$

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