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Question Number 12611 by tawa last updated on 26/Apr/17

$$\mathrm{A}\mathrm{drum}\mathrm{of}\mathrm{mass}100\mathrm{g}\mathrm{is}\mathrm{rolled}\mathrm{into}\mathrm{the}\mathrm{deck}\mathrm{of}\mathrm{a}\mathrm{lorry}1.5\mathrm{m}\mathrm{above}\mathrm{a}$$$$\mathrm{horizontal}\mathrm{floor}\mathrm{using}\mathrm{a}\mathrm{plank}4\mathrm{m}\mathrm{long}.\mathrm{calculate}\mathrm{the}\mathrm{workdone}\mathrm{against}$$$$\mathrm{gravity}\mathrm{during}\mathrm{the}\mathrm{process}.(\mathrm{g}=10\mathrm{m}/{\mathrm{s}}^2).$$

Answered by mrW1 last updated on 27/Apr/17

$$W=mgh=0.1\times 10\times 1.5=1.5J$$

Commented by tawa last updated on 27/Apr/17

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}.$$

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