A,B,C and D are angles of tetragon if A+D=240^(° ) , C+D=200g B+D=((2π)/3) , find D=???


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Question Number 126148 by Study last updated on 17/Dec/20

$A, B, C a n d D a r e a n g l e s o f t e t r a g o n$ $i f A + D = 240^{°}, C + D = 200 g$ $B + D = \frac{2 π}{3}, f i n d D = ? ? ?$
	Answered by mahdipoor last updated on 17/Dec/20

	$A + B + C + D = 360^{°}$ $A + D = 240^{°}$ $C + D = 200 g \times \frac{360^{°}}{400 g} = 180^{°}$ $B + D = \frac{2 π}{3} r a d \times \frac{360^{°}}{2 π r a d} = 120^{°}$ $\Rightarrow D = 90, B = 30, C = 90, A = 150$
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