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Question Number 126165 by TheMexicanTacosG last updated on 17/Dec/20

if: b^2 = −3 −c^2 +2(a−b−c) −a^2 calculate: a + b + c = ?

if:b2=−3−c2+2(a−b−c)−a2calculate:a+b+c=?

Commented by PRITHWISH SEN 2 last updated on 18/Dec/20

(a^2 −2a+1)+(b^2 +2b+1)+(c^2 +2c+1)=0 (a−1)^2 +(b+1)^2 +(c+1)^2 = 0 ⇒ a= 1, b=−1, c=−1 a+b+c=1−1−1=−1

(a2−2a+1)+(b2+2b+1)+(c2+2c+1)=0(a−1)2+(b+1)2+(c+1)2=0⇒a=1,b=−1,c=−1a+b+c=1−1−1=−1

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