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Question Number 126195 by bramlexs22 last updated on 18/Dec/20
limx→12x−sin(x−1)−2cos(x−1)arctan(x−1)−lnx?
Answered by liberty last updated on 18/Dec/20
letw=x−1L=limw→02w+1−sinw−2coswarctanw−ln(w+1)L=limw→02(1+w2−w28+O(w3))−(w+O(w3))−2(1−w22+O(w4))(w+O(w3))−(w−w22+O(w3))L=limw→03w24+O(w3)w22+O(w3)=limw→0w2(34+O(w))w2(12+O(w))L=34+012+0=32
Answered by bramlexs22 last updated on 18/Dec/20
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