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Question Number 126206 by amns last updated on 18/Dec/20

$$If(n>m),$$ $$\mathrm{then}\frac{a^m}{a^n}=a^{?}$$

Commented byamns last updated on 18/Dec/20

$$\mathrm{Is}\mathrm{the}\mathrm{ans}.a^{\frac{1}{n-m}}?$$

Answered by MJS_new last updated on 18/Dec/20

$$\frac{a^m}{a^n}=a^{m-n}$$ $$\mathrm{no}\mathrm{matter}\mathrm{if}m>n\mathrm{or}m<n$$ $$a^{-k}=\frac{1}{a^k}\Rightarrow a^{m-n}=\frac{1}{a^{n-m}}$$

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