Question and Answers Forum

All Questions      Topic List

Others Questions

Previous in All Question      Next in All Question      

Previous in Others      Next in Others      

Question Number 12631 by 786786AM last updated on 27/Apr/17

  Find tbe sloution set of (5/((x−3)(3+x))) > 0.

$$\:\:\mathrm{Find}\:\mathrm{tbe}\:\mathrm{sloution}\:\mathrm{set}\:\mathrm{of}\:\frac{\mathrm{5}}{\left(\mathrm{x}−\mathrm{3}\right)\left(\mathrm{3}+\mathrm{x}\right)}\:>\:\mathrm{0}. \\ $$

Answered by mrW1 last updated on 27/Apr/17

(x−3)(x+3)>0  x^2 −3^2 >0  x^2 >3^2   ∣x∣>3  x<−3 or x>3

$$\left({x}−\mathrm{3}\right)\left({x}+\mathrm{3}\right)>\mathrm{0} \\ $$ $${x}^{\mathrm{2}} −\mathrm{3}^{\mathrm{2}} >\mathrm{0} \\ $$ $${x}^{\mathrm{2}} >\mathrm{3}^{\mathrm{2}} \\ $$ $$\mid{x}\mid>\mathrm{3} \\ $$ $${x}<−\mathrm{3}\:{or}\:{x}>\mathrm{3} \\ $$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com