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Question Number 12631 by 786786AM last updated on 27/Apr/17

$$\mathrm{Find}\mathrm{tbe}\mathrm{sloution}\mathrm{set}\mathrm{of}\frac{5}{(\mathrm{x}-3)(3+\mathrm{x})}>0.$$

Answered by mrW1 last updated on 27/Apr/17

$$(x-3)(x+3)>0$$ $$x^2-3^2>0$$ $$x^2>3^2$$ $$\mid x\mid >3$$ $$x<-3orx>3$$

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