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Question Number 126502 by benjo_mathlover last updated on 21/Dec/20
∫dxsin5xcos7x?
Answered by MJS_new last updated on 21/Dec/20
∫dxsin5xcos7x=[t=tanx→dx=2cos2xtanxdt]=2∫(t4+1)2t4dt=∫(2t4+4+2t4)dt==25t5+4t−23t3=...
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