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Question Number 126520 by joki last updated on 21/Dec/20

$$\int \frac{\mathrm{x}}{\sqrt{1-{\mathrm{x}}^2}}\mathrm{dx}$$

Answered by liberty last updated on 21/Dec/20

$$-\frac{1}{2}\int \frac{d(1-x^2)}{\sqrt{1-x^2}}=-\frac{1}{2}\int {(1-x^2)}^{-\frac{1}{2}}d(1-x^2)$$$$=-\sqrt{1-x^2}+c$$

Answered by amns last updated on 21/Dec/20

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