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Question Number 126529 by Study last updated on 21/Dec/20

Commented by Olaf last updated on 22/Dec/20

$$\mathrm{Why}{x}^{\frac{1}{\ln x}}\mathrm{is}\mathrm{not}{e}^{\ln \left[x^{\frac{1}{\ln x}}\right]}=e^{\frac{1}{\ln x}\ln x}=e\mathrm{sir}?$$$$\mathrm{Why}\mathrm{the}\mathrm{result}\mathrm{is}\mathrm{not}e.x+\mathrm{C}?$$

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